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You are given the root of a binary tree structure where each node contains an integer value. The tree is organized into horizontal layers called depths, where the root node resides at depth 1, its immediate children are at depth 2, and this pattern continues downward for all subsequent nodes.
Your task is to analyze the tree by computing the aggregate value (sum of all node values) at each depth. Among all depths, identify the one with the highest aggregate value. If multiple depths share the same maximum aggregate value, return the topmost (smallest numbered) depth.
Key Observations:
This problem tests your understanding of tree traversal techniques and your ability to aggregate data across hierarchical levels efficiently.
root = [1,7,0,7,-8,null,null]2The tree has three depths: • Depth 1: Contains only the root node with value 1. Aggregate = 1. • Depth 2: Contains nodes with values 7 and 0. Aggregate = 7 + 0 = 7. • Depth 3: Contains nodes with values 7 and -8. Aggregate = 7 + (-8) = -1.
Depth 2 has the highest aggregate value of 7, so we return 2.
root = [989,null,10250,98693,-89388,null,null,null,-32127]2Analyzing the depth aggregates: • Depth 1: 989 • Depth 2: 10250 • Depth 3: 98693 + (-89388) = 9305 • Depth 4: -32127
Depth 2 has the maximum aggregate value of 10250.
root = [100,1,2,3,4,5,6]1The root alone at depth 1 has value 100. Depth 2 has aggregate 1 + 2 = 3. Depth 3 has aggregate 3 + 4 + 5 + 6 = 18. Since 100 > 18 > 3, depth 1 wins.
Constraints