Below is the implementation of the token strategy game:
12345678910111213141516171819202122232425262728293031323334353637383940/** * Greedy Approach with Sorting * Time Complexity: O(n log n) - Sorting the tokens takes O(n log n) time * Space Complexity: O(1) - We only use a constant amount of extra space * * @param {number[]} tokens - Array of token values * @param {number} power - Initial power * @return {number} - Maximum score achievable */function bagOfTokensScore(tokens, power) { // Sort tokens in ascending order tokens.sort((a, b) => a - b); let left = 0; let right = tokens.length - 1; let score = 0; let maxScore = 0; while (left <= right) { // If we can play the smallest token face up if (power >= tokens[left]) { power -= tokens[left]; left++; score++; maxScore = Math.max(maxScore, score); } // If we can play the largest token face down else if (score > 0) { power += tokens[right]; right--; score--; } // If we can't make any move else { break; } } return maxScore;}
Let's break down the implementation:
Implement the token strategy game solution in different programming languages.
Below is the implementation of the token strategy game in different programming languages. Select a language tab to view the corresponding code.
12345678910111213141516171819202122232425262728293031323334353637383940/** * Greedy Approach with Sorting * Time Complexity: O(n log n) - Sorting the tokens takes O(n log n) time * Space Complexity: O(1) - We only use a constant amount of extra space * * @param {number[]} tokens - Array of token values * @param {number} power - Initial power * @return {number} - Maximum score achievable */function bagOfTokensScore(tokens, power) { // Sort tokens in ascending order tokens.sort((a, b) => a - b); let left = 0; let right = tokens.length - 1; let score = 0; let maxScore = 0; while (left <= right) { // If we can play the smallest token face up if (power >= tokens[left]) { power -= tokens[left]; left++; score++; maxScore = Math.max(maxScore, score); } // If we can play the largest token face down else if (score > 0) { power += tokens[right]; right--; score--; } // If we can't make any move else { break; } } return maxScore;}
First, understand that we need to maximize our score by strategically playing tokens either face up or face down.
Sort the tokens in ascending order to easily access the smallest and largest tokens.
Use two pointers to track the smallest and largest tokens that haven't been played yet.
Play the smallest tokens face up and the largest tokens face down, always choosing the move that maximizes our score.
Keep track of the maximum score achieved during the game, as we might temporarily decrease our score to gain more power.
Consider edge cases such as empty token arrays or when we don't have enough power to play any token.
Verify the solution with the provided examples and additional test cases.
Modify the code to implement an alternative approach and test it with the same examples.
Implement a function that solves the token strategy game problem using a different approach than shown above.
If there are no tokens, the maximum score is 0.
If the initial power is less than the smallest token value, we can't play any token face up initially.
If we have enough power to play all tokens face up, the maximum score is the number of tokens.
Sometimes, it's beneficial to temporarily decrease our score by playing a token face down to gain more power.
Below is the implementation of the token strategy game:
12345678910111213141516171819202122232425262728293031323334353637383940/** * Greedy Approach with Sorting * Time Complexity: O(n log n) - Sorting the tokens takes O(n log n) time * Space Complexity: O(1) - We only use a constant amount of extra space * * @param {number[]} tokens - Array of token values * @param {number} power - Initial power * @return {number} - Maximum score achievable */function bagOfTokensScore(tokens, power) { // Sort tokens in ascending order tokens.sort((a, b) => a - b); let left = 0; let right = tokens.length - 1; let score = 0; let maxScore = 0; while (left <= right) { // If we can play the smallest token face up if (power >= tokens[left]) { power -= tokens[left]; left++; score++; maxScore = Math.max(maxScore, score); } // If we can play the largest token face down else if (score > 0) { power += tokens[right]; right--; score--; } // If we can't make any move else { break; } } return maxScore;}
Let's break down the implementation:
Implement the token strategy game solution in different programming languages.
Below is the implementation of the token strategy game in different programming languages. Select a language tab to view the corresponding code.
12345678910111213141516171819202122232425262728293031323334353637383940/** * Greedy Approach with Sorting * Time Complexity: O(n log n) - Sorting the tokens takes O(n log n) time * Space Complexity: O(1) - We only use a constant amount of extra space * * @param {number[]} tokens - Array of token values * @param {number} power - Initial power * @return {number} - Maximum score achievable */function bagOfTokensScore(tokens, power) { // Sort tokens in ascending order tokens.sort((a, b) => a - b); let left = 0; let right = tokens.length - 1; let score = 0; let maxScore = 0; while (left <= right) { // If we can play the smallest token face up if (power >= tokens[left]) { power -= tokens[left]; left++; score++; maxScore = Math.max(maxScore, score); } // If we can play the largest token face down else if (score > 0) { power += tokens[right]; right--; score--; } // If we can't make any move else { break; } } return maxScore;}
First, understand that we need to maximize our score by strategically playing tokens either face up or face down.
Sort the tokens in ascending order to easily access the smallest and largest tokens.
Use two pointers to track the smallest and largest tokens that haven't been played yet.
Play the smallest tokens face up and the largest tokens face down, always choosing the move that maximizes our score.
Keep track of the maximum score achieved during the game, as we might temporarily decrease our score to gain more power.
Consider edge cases such as empty token arrays or when we don't have enough power to play any token.
Verify the solution with the provided examples and additional test cases.
Modify the code to implement an alternative approach and test it with the same examples.
Implement a function that solves the token strategy game problem using a different approach than shown above.
If there are no tokens, the maximum score is 0.
If the initial power is less than the smallest token value, we can't play any token face up initially.
If we have enough power to play all tokens face up, the maximum score is the number of tokens.
Sometimes, it's beneficial to temporarily decrease our score by playing a token face down to gain more power.