Below is the implementation of the tower of hanoi puzzle solver:
12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849function towerOfHanoi(n, source, auxiliary, target) { // Base case: only one disk to move if (n === 1) { console.log(`Move disk 1 from ${source} to ${target}`); return; } // Step 1: Move n-1 disks from source to auxiliary towerOfHanoi(n - 1, source, target, auxiliary); // Step 2: Move the largest disk from source to target console.log(`Move disk ${n} from ${source} to ${target}`); // Step 3: Move n-1 disks from auxiliary to target towerOfHanoi(n - 1, auxiliary, source, target);} // Test casesconsole.log("Tower of Hanoi with 1 disk:");towerOfHanoi(1, 'A', 'B', 'C');// Output: Move disk 1 from A to C console.log("\nTower of Hanoi with 2 disks:");towerOfHanoi(2, 'A', 'B', 'C');// Output:// Move disk 1 from A to B// Move disk 2 from A to C// Move disk 1 from B to C console.log("\nTower of Hanoi with 3 disks:");towerOfHanoi(3, 'A', 'B', 'C');// Output:// Move disk 1 from A to C// Move disk 2 from A to B// Move disk 1 from C to B// Move disk 3 from A to C// Move disk 1 from B to A// Move disk 2 from B to C// Move disk 1 from A to C // Calculate the number of moves for n disksfunction calculateMoves(n) { return Math.pow(2, n) - 1;} console.log("\nNumber of moves required:");for (let i = 1; i <= 5; i++) { console.log(`For ${i} disk(s): ${calculateMoves(i)} moves`);}
Let's break down the implementation:
Implement the tower of hanoi puzzle solver solution in different programming languages.
Below is the implementation of the tower of hanoi puzzle solver in different programming languages. Select a language tab to view the corresponding code.
12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849function towerOfHanoi(n, source, auxiliary, target) { // Base case: only one disk to move if (n === 1) { console.log(`Move disk 1 from ${source} to ${target}`); return; } // Step 1: Move n-1 disks from source to auxiliary towerOfHanoi(n - 1, source, target, auxiliary); // Step 2: Move the largest disk from source to target console.log(`Move disk ${n} from ${source} to ${target}`); // Step 3: Move n-1 disks from auxiliary to target towerOfHanoi(n - 1, auxiliary, source, target);} // Test casesconsole.log("Tower of Hanoi with 1 disk:");towerOfHanoi(1, 'A', 'B', 'C');// Output: Move disk 1 from A to C console.log("\nTower of Hanoi with 2 disks:");towerOfHanoi(2, 'A', 'B', 'C');// Output:// Move disk 1 from A to B// Move disk 2 from A to C// Move disk 1 from B to C console.log("\nTower of Hanoi with 3 disks:");towerOfHanoi(3, 'A', 'B', 'C');// Output:// Move disk 1 from A to C// Move disk 2 from A to B// Move disk 1 from C to B// Move disk 3 from A to C// Move disk 1 from B to A// Move disk 2 from B to C// Move disk 1 from A to C // Calculate the number of moves for n disksfunction calculateMoves(n) { return Math.pow(2, n) - 1;} console.log("\nNumber of moves required:");for (let i = 1; i <= 5; i++) { console.log(`For ${i} disk(s): ${calculateMoves(i)} moves`);}
The Tower of Hanoi puzzle involves moving a stack of disks from one rod to another, following specific rules about disk movement.
Recognize that moving n disks can be broken down into moving n-1 disks, then moving the largest disk, then moving n-1 disks again.
The simplest case is moving a single disk directly from the source to the target rod.
Write a function that handles the base case and implements the three-step recursive approach for the general case.
Understand that the number of moves required is 2^n - 1, which grows exponentially with the number of disks.
Modify the code to implement an alternative approach and test it with the same examples.
Implement a function that solves the tower of hanoi puzzle solver problem using a different approach than shown above.
With only one disk, the solution is trivial: move the disk directly from source to target.
The number of moves grows exponentially with the number of disks, potentially leading to very long output.
The algorithm works regardless of how the rods are named, as long as the names are used consistently.
Below is the implementation of the tower of hanoi puzzle solver:
12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849function towerOfHanoi(n, source, auxiliary, target) { // Base case: only one disk to move if (n === 1) { console.log(`Move disk 1 from ${source} to ${target}`); return; } // Step 1: Move n-1 disks from source to auxiliary towerOfHanoi(n - 1, source, target, auxiliary); // Step 2: Move the largest disk from source to target console.log(`Move disk ${n} from ${source} to ${target}`); // Step 3: Move n-1 disks from auxiliary to target towerOfHanoi(n - 1, auxiliary, source, target);} // Test casesconsole.log("Tower of Hanoi with 1 disk:");towerOfHanoi(1, 'A', 'B', 'C');// Output: Move disk 1 from A to C console.log("\nTower of Hanoi with 2 disks:");towerOfHanoi(2, 'A', 'B', 'C');// Output:// Move disk 1 from A to B// Move disk 2 from A to C// Move disk 1 from B to C console.log("\nTower of Hanoi with 3 disks:");towerOfHanoi(3, 'A', 'B', 'C');// Output:// Move disk 1 from A to C// Move disk 2 from A to B// Move disk 1 from C to B// Move disk 3 from A to C// Move disk 1 from B to A// Move disk 2 from B to C// Move disk 1 from A to C // Calculate the number of moves for n disksfunction calculateMoves(n) { return Math.pow(2, n) - 1;} console.log("\nNumber of moves required:");for (let i = 1; i <= 5; i++) { console.log(`For ${i} disk(s): ${calculateMoves(i)} moves`);}
Let's break down the implementation:
Implement the tower of hanoi puzzle solver solution in different programming languages.
Below is the implementation of the tower of hanoi puzzle solver in different programming languages. Select a language tab to view the corresponding code.
12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849function towerOfHanoi(n, source, auxiliary, target) { // Base case: only one disk to move if (n === 1) { console.log(`Move disk 1 from ${source} to ${target}`); return; } // Step 1: Move n-1 disks from source to auxiliary towerOfHanoi(n - 1, source, target, auxiliary); // Step 2: Move the largest disk from source to target console.log(`Move disk ${n} from ${source} to ${target}`); // Step 3: Move n-1 disks from auxiliary to target towerOfHanoi(n - 1, auxiliary, source, target);} // Test casesconsole.log("Tower of Hanoi with 1 disk:");towerOfHanoi(1, 'A', 'B', 'C');// Output: Move disk 1 from A to C console.log("\nTower of Hanoi with 2 disks:");towerOfHanoi(2, 'A', 'B', 'C');// Output:// Move disk 1 from A to B// Move disk 2 from A to C// Move disk 1 from B to C console.log("\nTower of Hanoi with 3 disks:");towerOfHanoi(3, 'A', 'B', 'C');// Output:// Move disk 1 from A to C// Move disk 2 from A to B// Move disk 1 from C to B// Move disk 3 from A to C// Move disk 1 from B to A// Move disk 2 from B to C// Move disk 1 from A to C // Calculate the number of moves for n disksfunction calculateMoves(n) { return Math.pow(2, n) - 1;} console.log("\nNumber of moves required:");for (let i = 1; i <= 5; i++) { console.log(`For ${i} disk(s): ${calculateMoves(i)} moves`);}
The Tower of Hanoi puzzle involves moving a stack of disks from one rod to another, following specific rules about disk movement.
Recognize that moving n disks can be broken down into moving n-1 disks, then moving the largest disk, then moving n-1 disks again.
The simplest case is moving a single disk directly from the source to the target rod.
Write a function that handles the base case and implements the three-step recursive approach for the general case.
Understand that the number of moves required is 2^n - 1, which grows exponentially with the number of disks.
Modify the code to implement an alternative approach and test it with the same examples.
Implement a function that solves the tower of hanoi puzzle solver problem using a different approach than shown above.
With only one disk, the solution is trivial: move the disk directly from source to target.
The number of moves grows exponentially with the number of disks, potentially leading to very long output.
The algorithm works regardless of how the rods are named, as long as the names are used consistently.