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Problem Statement

Knight Dialer

The chess knight has a unique movement, it may move two squares vertically and one square horizontally, or two squares horizontally and one square vertically (with both forming the shape of an L). The possible movements of chess knight are shown in this diagram:

Knight Moves

A chess knight can move as indicated in the chess diagram below:

Phone Keypad

We have a chess knight and a phone pad as shown above, the knight can only stand on a numeric cell (i.e. blue cell).

Given an integer n, return how many distinct phone numbers of length n we can dial.

You are allowed to place the knight on any numeric cell initially and then you should perform n - 1 jumps to dial a number of length n. All jumps should be valid knight jumps.

As the answer may be very large, return the answer modulo 10^9 + 7.

Examples

Example 1:

Input: n = 1
Output: 10
Explanation: We need to dial a number of length 1, so placing the knight over any numeric cell of the 10 cells is sufficient.

Example 2:

Input: n = 2
Output: 20
Explanation: All possible valid knight moves from any numeric cell to dial a number of length 2 are: Knight at cell 1 can jump to cell 6 and 8 Knight at cell 2 can jump to cell 7 and 9 Knight at cell 3 can jump to cell 4 and 8 Knight at cell 4 can jump to cell 3 and 9 and 0 Knight at cell 5 cannot jump to any cell Knight at cell 6 can jump to cell 1 and 7 and 0 Knight at cell 7 can jump to cell 2 and 6 Knight at cell 8 can jump to cell 1 and 3 Knight at cell 9 can jump to cell 2 and 4 Knight at cell 0 can jump to cell 4 and 6 Thus the total number of distinct phone numbers we can dial is 20.

Example 3:

Input: n = 3131
Output: 136006598
Explanation: Please take the answer modulo 10^9 + 7.

Constraints

  • 1 <= n <= 5000

Problem Breakdown

To solve this problem, we need to:

  1. This problem can be solved using dynamic programming.
  2. We need to keep track of the number of ways to reach each digit after a certain number of jumps.
  3. The state of the DP array is defined by the current digit and the number of jumps made so far.
  4. The recurrence relation involves considering all possible previous digits that can lead to the current digit.
  5. The modulo operation needs to be applied at each step to avoid integer overflow.
ProblemSolutionCode
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