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Solution Approach

Solution Overview

There are 2 main approaches to solve this problem:

  1. Two Pointers Approach - Complex approach
  2. Built-in Functions Approach - Complex approach

Approach 1: Two Pointers Approach

The most efficient way to reverse a string is to use the two pointers technique. We'll place one pointer at the beginning of the string and another at the end, then swap the characters and move the pointers toward each other until they meet in the middle.

0h
1e
2l
3l
4o
Swap 'h' and 'o'
0o
1e
2l
3l
4h
Swap 'e' and 'l'
0o
1l
2l
3e
4h

Algorithm:

  1. Initialize two pointers: left at the start (index 0) and right at the end (index length-1) of the string.
  2. While left < right, swap the characters at the left and right positions.
  3. Increment left and decrement right to move the pointers toward the center.
  4. Continue until the pointers meet or cross each other.
  5. Return the reversed string.

Time Complexity:

O(n)

where n is the length of the string. We need to process each character once.

Space Complexity:

O(1)

for languages with mutable strings. We only need a constant amount of extra space for the pointers and temporary variables.

Approach 2: Built-in Functions Approach

Many programming languages provide built-in functions or methods to reverse a string. While this approach is simpler to implement, it's important to understand the underlying mechanism.

h
e
l
l
o
o
l
l
e
h

Algorithm:

  1. Convert the string to an array of characters (if needed).
  2. Use the built-in reverse function or method.
  3. Convert the array back to a string (if needed).
  4. Return the reversed string.

Time Complexity:

O(n)

where n is the length of the string. The built-in functions typically process each character once.

Space Complexity:

O(n)

Most built-in functions create a new string or array, requiring space proportional to the input size.

Pseudocode

solution.pseudo
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function reverseString(s):
left = 0
right = s.length - 1
while left < right:
// Swap characters at left and right indices
temp = s[left]
s[left] = s[right]
s[right] = temp
// Move pointers towards the middle
left++
right--
return s
ProblemSolutionCode
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