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Problem Statement

Word Frequency Analyzer

You're building a text analysis tool that needs to identify the most commonly used words in a document.

Given a non-empty array of strings words, return the k most frequent elements.

Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first.

Examples

Example 1:

Input: words = ["i", "love", "leetcode", "i", "love", "coding"], k = 2
Output: ["i", "love"]
Explanation: "i" and "love" are the two most frequent words. Note that "i" comes before "love" due to a lower alphabetical order.

Example 2:

Input: words = ["the", "day", "is", "sunny", "the", "the", "the", "sunny", "is", "is"], k = 4
Output: ["the", "is", "sunny", "day"]
Explanation: "the", "is", "sunny" and "day" are the four most frequent words, with the number of occurrence being 4, 3, 2 and 1 respectively.

Constraints

  • 1 <= words.length <= 500
  • 1 <= words[i].length <= 10
  • words[i] consists of lowercase English letters
  • k is in the range [1, the number of unique words[i]]

Problem Breakdown

To solve this problem, we need to:

  1. We need to count the frequency of each word in the array
  2. Words with higher frequencies should appear before words with lower frequencies
  3. If two words have the same frequency, they should be sorted alphabetically
  4. A hash map or frequency counter is useful for tracking word frequencies
  5. A priority queue (heap) can efficiently find the k most frequent elements
  6. The problem can also be solved by sorting all words by their frequencies
ProblemSolutionCode
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