Below is the implementation of the prime factor sequence:
12345678910111213141516171819202122232425262728293031323334353637383940414243/** * Dynamic Programming Approach * Time Complexity: O(n) - We perform a constant amount of work for each of the n ugly numbers * Space Complexity: O(n) - We need to store all n ugly numbers in the dp array * * @param {number} n - The position of the ugly number to find * @return {number} - The nth ugly number */function nthUglyNumber(n) { // Initialize the dp array with the first ugly number const dp = new Array(n); dp[0] = 1; // Initialize three pointers for multiplying by 2, 3, and 5 let p2 = 0; let p3 = 0; let p5 = 0; // Generate the remaining ugly numbers for (let i = 1; i < n; i++) { // Calculate the next potential ugly numbers const next2 = dp[p2] * 2; const next3 = dp[p3] * 3; const next5 = dp[p5] * 5; // Take the minimum of the three potential ugly numbers dp[i] = Math.min(next2, next3, next5); // Update the pointers if (dp[i] === next2) { p2++; } if (dp[i] === next3) { p3++; } if (dp[i] === next5) { p5++; } } // Return the nth ugly number return dp[n - 1];}
Let's break down the implementation:
Implement the prime factor sequence solution in different programming languages.
Below is the implementation of the prime factor sequence in different programming languages. Select a language tab to view the corresponding code.
12345678910111213141516171819202122232425262728293031323334353637383940414243/** * Dynamic Programming Approach * Time Complexity: O(n) - We perform a constant amount of work for each of the n ugly numbers * Space Complexity: O(n) - We need to store all n ugly numbers in the dp array * * @param {number} n - The position of the ugly number to find * @return {number} - The nth ugly number */function nthUglyNumber(n) { // Initialize the dp array with the first ugly number const dp = new Array(n); dp[0] = 1; // Initialize three pointers for multiplying by 2, 3, and 5 let p2 = 0; let p3 = 0; let p5 = 0; // Generate the remaining ugly numbers for (let i = 1; i < n; i++) { // Calculate the next potential ugly numbers const next2 = dp[p2] * 2; const next3 = dp[p3] * 3; const next5 = dp[p5] * 5; // Take the minimum of the three potential ugly numbers dp[i] = Math.min(next2, next3, next5); // Update the pointers if (dp[i] === next2) { p2++; } if (dp[i] === next3) { p3++; } if (dp[i] === next5) { p5++; } } // Return the nth ugly number return dp[n - 1];}
First, understand that we need to find the nth ugly number, where an ugly number is a positive integer whose prime factors are limited to 2, 3, and 5.
Recognize that every ugly number (except 1) can be generated by multiplying a previous ugly number by either 2, 3, or 5.
Use dynamic programming to generate the sequence of ugly numbers by maintaining three pointers to track which previous ugly numbers to multiply by 2, 3, and 5.
Alternatively, use a min heap to efficiently find the next ugly number in the sequence by keeping track of all potential next ugly numbers.
Consider edge cases such as n = 1, where the answer is 1.
Choose the most efficient approach based on the constraints of the problem.
Verify the solution with the provided examples and additional test cases.
Modify the code to implement an alternative approach and test it with the same examples.
Implement a function that solves the prime factor sequence problem using a different approach than shown above.
The first ugly number is 1.
Multiple combinations can produce the same ugly number (e.g., 2*3 and 3*2 both equal 6).
The problem states that n does not exceed 1690, so we need to ensure our solution can handle this range efficiently.
Below is the implementation of the prime factor sequence:
12345678910111213141516171819202122232425262728293031323334353637383940414243/** * Dynamic Programming Approach * Time Complexity: O(n) - We perform a constant amount of work for each of the n ugly numbers * Space Complexity: O(n) - We need to store all n ugly numbers in the dp array * * @param {number} n - The position of the ugly number to find * @return {number} - The nth ugly number */function nthUglyNumber(n) { // Initialize the dp array with the first ugly number const dp = new Array(n); dp[0] = 1; // Initialize three pointers for multiplying by 2, 3, and 5 let p2 = 0; let p3 = 0; let p5 = 0; // Generate the remaining ugly numbers for (let i = 1; i < n; i++) { // Calculate the next potential ugly numbers const next2 = dp[p2] * 2; const next3 = dp[p3] * 3; const next5 = dp[p5] * 5; // Take the minimum of the three potential ugly numbers dp[i] = Math.min(next2, next3, next5); // Update the pointers if (dp[i] === next2) { p2++; } if (dp[i] === next3) { p3++; } if (dp[i] === next5) { p5++; } } // Return the nth ugly number return dp[n - 1];}
Let's break down the implementation:
Implement the prime factor sequence solution in different programming languages.
Below is the implementation of the prime factor sequence in different programming languages. Select a language tab to view the corresponding code.
12345678910111213141516171819202122232425262728293031323334353637383940414243/** * Dynamic Programming Approach * Time Complexity: O(n) - We perform a constant amount of work for each of the n ugly numbers * Space Complexity: O(n) - We need to store all n ugly numbers in the dp array * * @param {number} n - The position of the ugly number to find * @return {number} - The nth ugly number */function nthUglyNumber(n) { // Initialize the dp array with the first ugly number const dp = new Array(n); dp[0] = 1; // Initialize three pointers for multiplying by 2, 3, and 5 let p2 = 0; let p3 = 0; let p5 = 0; // Generate the remaining ugly numbers for (let i = 1; i < n; i++) { // Calculate the next potential ugly numbers const next2 = dp[p2] * 2; const next3 = dp[p3] * 3; const next5 = dp[p5] * 5; // Take the minimum of the three potential ugly numbers dp[i] = Math.min(next2, next3, next5); // Update the pointers if (dp[i] === next2) { p2++; } if (dp[i] === next3) { p3++; } if (dp[i] === next5) { p5++; } } // Return the nth ugly number return dp[n - 1];}
First, understand that we need to find the nth ugly number, where an ugly number is a positive integer whose prime factors are limited to 2, 3, and 5.
Recognize that every ugly number (except 1) can be generated by multiplying a previous ugly number by either 2, 3, or 5.
Use dynamic programming to generate the sequence of ugly numbers by maintaining three pointers to track which previous ugly numbers to multiply by 2, 3, and 5.
Alternatively, use a min heap to efficiently find the next ugly number in the sequence by keeping track of all potential next ugly numbers.
Consider edge cases such as n = 1, where the answer is 1.
Choose the most efficient approach based on the constraints of the problem.
Verify the solution with the provided examples and additional test cases.
Modify the code to implement an alternative approach and test it with the same examples.
Implement a function that solves the prime factor sequence problem using a different approach than shown above.
The first ugly number is 1.
Multiple combinations can produce the same ugly number (e.g., 2*3 and 3*2 both equal 6).
The problem states that n does not exceed 1690, so we need to ensure our solution can handle this range efficiently.