You are given a rows x cols
matrix grid
representing a field of cherries where grid[i][j]
represents the number of cherries that you can collect from the (i, j)
cell.
You have two robots that can collect cherries for you:
(0, 0)
, and(0, cols - 1)
.Return the maximum number of cherries collection using both robots by following the rules below:
(i, j)
, robots can move to cell (i + 1, j - 1)
, (i + 1, j)
, or (i + 1, j + 1)
.grid
.Input: grid = [[3,1,1],[2,5,1],[1,5,5],[2,1,1]]
Output: 24
Explanation: Path of robot #1 and #2 are described in color green and blue respectively.
Cherries taken by Robot #1, (3 + 2 + 5 + 2) = 12.
Cherries taken by Robot #2, (1 + 5 + 5 + 1) = 12.
Total of cherries: 12 + 12 = 24.
Input: grid = [[1,0,0,0,0,0,1],[2,0,0,0,0,3,0],[2,0,9,0,0,0,0],[0,3,0,5,4,0,0],[1,0,2,3,0,0,6]]
Output: 28
Explanation: Path of robot #1 and #2 are described in color green and blue respectively.
Cherries taken by Robot #1, (1 + 2 + 2 + 0 + 1) = 6.
Cherries taken by Robot #2, (1 + 3 + 0 + 4 + 6) = 14.
Cherries taken by both robots, (0 + 0 + 9 + 5 + 3) = 17.
Total of cherries: 6 + 14 - 9 = 28.
To solve this problem, we need to:
Apply string manipulation concepts to solve a real-world problem.
You are given a rows x cols
matrix grid
representing a field of cherries where grid[i][j]
represents the number of cherries that you can collect from the (i, j)
cell.
You have two robots that can collect cherries for you:
(0, 0)
, and(0, cols - 1)
.Return the maximum number of cherries collection using both robots by following the rules below:
(i, j)
, robots can move to cell (i + 1, j - 1)
, (i + 1, j)
, or (i + 1, j + 1)
.grid
.Path of robot #1 and #2 are described in color green and blue respectively. Cherries taken by Robot #1, (3 + 2 + 5 + 2) = 12. Cherries taken by Robot #2, (1 + 5 + 5 + 1) = 12. Total of cherries: 12 + 12 = 24.
Path of robot #1 and #2 are described in color green and blue respectively. Cherries taken by Robot #1, (1 + 2 + 2 + 0 + 1) = 6. Cherries taken by Robot #2, (1 + 3 + 0 + 4 + 6) = 14. Cherries taken by both robots, (0 + 0 + 9 + 5 + 3) = 17. Total of cherries: 6 + 14 - 9 = 28.
This problem can be solved using dynamic programming.
The key insight is to move both robots simultaneously, row by row.
For each row, we need to consider all possible positions of both robots.
We can use a 3D DP array dp[row][col1][col2] to represent the maximum cherries that can be collected when robot 1 is at (row, col1) and robot 2 is at (row, col2).
For each state, we need to consider 9 possible transitions (3 possible moves for each robot).
We need to be careful about the case where both robots are in the same cell, as only one robot can collect cherries from that cell.
This problem has several practical applications:
Optimizing the collection of resources in a grid-based environment, such as robots collecting items in a warehouse.
Coordinating multiple agents to maximize the total reward in a shared environment.
Planning optimal paths for multiple agents in a shared environment, ensuring they don't interfere with each other.
You are given a rows x cols
matrix grid
representing a field of cherries where grid[i][j]
represents the number of cherries that you can collect from the (i, j)
cell.
You have two robots that can collect cherries for you:
(0, 0)
, and(0, cols - 1)
.Return the maximum number of cherries collection using both robots by following the rules below:
(i, j)
, robots can move to cell (i + 1, j - 1)
, (i + 1, j)
, or (i + 1, j + 1)
.grid
.Input: grid = [[3,1,1],[2,5,1],[1,5,5],[2,1,1]]
Output: 24
Explanation: Path of robot #1 and #2 are described in color green and blue respectively.
Cherries taken by Robot #1, (3 + 2 + 5 + 2) = 12.
Cherries taken by Robot #2, (1 + 5 + 5 + 1) = 12.
Total of cherries: 12 + 12 = 24.
Input: grid = [[1,0,0,0,0,0,1],[2,0,0,0,0,3,0],[2,0,9,0,0,0,0],[0,3,0,5,4,0,0],[1,0,2,3,0,0,6]]
Output: 28
Explanation: Path of robot #1 and #2 are described in color green and blue respectively.
Cherries taken by Robot #1, (1 + 2 + 2 + 0 + 1) = 6.
Cherries taken by Robot #2, (1 + 3 + 0 + 4 + 6) = 14.
Cherries taken by both robots, (0 + 0 + 9 + 5 + 3) = 17.
Total of cherries: 6 + 14 - 9 = 28.
To solve this problem, we need to:
Apply string manipulation concepts to solve a real-world problem.
You are given a rows x cols
matrix grid
representing a field of cherries where grid[i][j]
represents the number of cherries that you can collect from the (i, j)
cell.
You have two robots that can collect cherries for you:
(0, 0)
, and(0, cols - 1)
.Return the maximum number of cherries collection using both robots by following the rules below:
(i, j)
, robots can move to cell (i + 1, j - 1)
, (i + 1, j)
, or (i + 1, j + 1)
.grid
.Path of robot #1 and #2 are described in color green and blue respectively. Cherries taken by Robot #1, (3 + 2 + 5 + 2) = 12. Cherries taken by Robot #2, (1 + 5 + 5 + 1) = 12. Total of cherries: 12 + 12 = 24.
Path of robot #1 and #2 are described in color green and blue respectively. Cherries taken by Robot #1, (1 + 2 + 2 + 0 + 1) = 6. Cherries taken by Robot #2, (1 + 3 + 0 + 4 + 6) = 14. Cherries taken by both robots, (0 + 0 + 9 + 5 + 3) = 17. Total of cherries: 6 + 14 - 9 = 28.
This problem can be solved using dynamic programming.
The key insight is to move both robots simultaneously, row by row.
For each row, we need to consider all possible positions of both robots.
We can use a 3D DP array dp[row][col1][col2] to represent the maximum cherries that can be collected when robot 1 is at (row, col1) and robot 2 is at (row, col2).
For each state, we need to consider 9 possible transitions (3 possible moves for each robot).
We need to be careful about the case where both robots are in the same cell, as only one robot can collect cherries from that cell.
This problem has several practical applications:
Optimizing the collection of resources in a grid-based environment, such as robots collecting items in a warehouse.
Coordinating multiple agents to maximize the total reward in a shared environment.
Planning optimal paths for multiple agents in a shared environment, ensuring they don't interfere with each other.