You're a mathematics researcher studying combinatorial patterns. You need to extract a specific row from Pascal's Triangle for your calculations, but you want to do it efficiently without generating the entire triangle.
In Pascal's Triangle, each number is the sum of the two numbers directly above it. The first row is always [1].
Given a row index rowIndex
(0-indexed), your task is to return the rowIndex
th row of Pascal's Triangle.
For example, when rowIndex = 3
, you should return the 4th row [1,3,3,1].
Follow-up: Could you optimize your algorithm to use only O(rowIndex) extra space?
Input: rowIndex = 3
Output: [1,3,3,1]
Explanation: The 4th row (0-indexed 3rd row) of Pascal's Triangle.
Input: rowIndex = 0
Output: [1]
Explanation: The 1st row (0-indexed 0th row) is just [1].
Input: rowIndex = 1
Output: [1,1]
Explanation: The 2nd row (0-indexed 1st row) is [1,1].
To solve this problem, we need to:
Apply string manipulation concepts to solve a real-world problem.
You're a mathematics researcher studying combinatorial patterns. You need to extract a specific row from Pascal's Triangle for your calculations, but you want to do it efficiently without generating the entire triangle.
In Pascal's Triangle, each number is the sum of the two numbers directly above it. The first row is always [1].
Given a row index rowIndex
(0-indexed), your task is to return the rowIndex
th row of Pascal's Triangle.
For example, when rowIndex = 3
, you should return the 4th row [1,3,3,1].
Follow-up: Could you optimize your algorithm to use only O(rowIndex) extra space?
The 4th row (0-indexed 3rd row) of Pascal's Triangle.
The 1st row (0-indexed 0th row) is just [1].
The 2nd row (0-indexed 1st row) is [1,1].
Each row starts and ends with 1
Each element inside a row is the sum of the two elements above it
The rowIndex-th row has rowIndex+1 elements
The row is symmetric around its center
The sum of the elements in the rowIndex-th row is 2^rowIndex
Each row represents the coefficients of the binomial expansion (a+b)^rowIndex
We can compute the row directly using the formula C(rowIndex, i) = rowIndex! / (i! * (rowIndex-i)!)
We can also compute the row iteratively using the property C(n, k) = C(n, k-1) * (n-k+1) / k
This problem has several practical applications:
Studying combinatorial patterns and binomial coefficients in advanced mathematics.
Computing probabilities in various scenarios, such as coin flips and dice rolls.
Solving problems related to combinations and permutations in computer science.
Analyzing data distributions and calculating binomial distributions.
You're a mathematics researcher studying combinatorial patterns. You need to extract a specific row from Pascal's Triangle for your calculations, but you want to do it efficiently without generating the entire triangle.
In Pascal's Triangle, each number is the sum of the two numbers directly above it. The first row is always [1].
Given a row index rowIndex
(0-indexed), your task is to return the rowIndex
th row of Pascal's Triangle.
For example, when rowIndex = 3
, you should return the 4th row [1,3,3,1].
Follow-up: Could you optimize your algorithm to use only O(rowIndex) extra space?
Input: rowIndex = 3
Output: [1,3,3,1]
Explanation: The 4th row (0-indexed 3rd row) of Pascal's Triangle.
Input: rowIndex = 0
Output: [1]
Explanation: The 1st row (0-indexed 0th row) is just [1].
Input: rowIndex = 1
Output: [1,1]
Explanation: The 2nd row (0-indexed 1st row) is [1,1].
To solve this problem, we need to:
Apply string manipulation concepts to solve a real-world problem.
You're a mathematics researcher studying combinatorial patterns. You need to extract a specific row from Pascal's Triangle for your calculations, but you want to do it efficiently without generating the entire triangle.
In Pascal's Triangle, each number is the sum of the two numbers directly above it. The first row is always [1].
Given a row index rowIndex
(0-indexed), your task is to return the rowIndex
th row of Pascal's Triangle.
For example, when rowIndex = 3
, you should return the 4th row [1,3,3,1].
Follow-up: Could you optimize your algorithm to use only O(rowIndex) extra space?
The 4th row (0-indexed 3rd row) of Pascal's Triangle.
The 1st row (0-indexed 0th row) is just [1].
The 2nd row (0-indexed 1st row) is [1,1].
Each row starts and ends with 1
Each element inside a row is the sum of the two elements above it
The rowIndex-th row has rowIndex+1 elements
The row is symmetric around its center
The sum of the elements in the rowIndex-th row is 2^rowIndex
Each row represents the coefficients of the binomial expansion (a+b)^rowIndex
We can compute the row directly using the formula C(rowIndex, i) = rowIndex! / (i! * (rowIndex-i)!)
We can also compute the row iteratively using the property C(n, k) = C(n, k-1) * (n-k+1) / k
This problem has several practical applications:
Studying combinatorial patterns and binomial coefficients in advanced mathematics.
Computing probabilities in various scenarios, such as coin flips and dice rolls.
Solving problems related to combinations and permutations in computer science.
Analyzing data distributions and calculating binomial distributions.