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Problem Statement

Shift Scheduler

You're the manager of a small café, "JavaBeans," that employs several baristas. Each week, you need to create a new work schedule, ensuring that all possible arrangements of baristas are considered to maintain fairness and variety in the scheduling.

To make this process more efficient, you're developing a scheduling tool that generates all possible permutations (arrangements) of baristas for the shifts. This will allow you to review all options and select the most suitable schedule based on individual preferences, availability, and other factors.

Your task is to implement a function that takes an array of barista names and returns all possible permutations (arrangements) of these baristas. This will help you visualize all possible scheduling options at once.

Examples

Example 1:

Input: baristas = ['Ana', 'Bob', 'Carlos']
Output: [['Ana', 'Bob', 'Carlos'], ['Ana', 'Carlos', 'Bob'], ['Bob', 'Ana', 'Carlos'], ['Bob', 'Carlos', 'Ana'], ['Carlos', 'Ana', 'Bob'], ['Carlos', 'Bob', 'Ana']]
Explanation: There are 6 (3!) possible arrangements of 3 baristas.

Example 2:

Input: baristas = ['Dana', 'Eli']
Output: [['Dana', 'Eli'], ['Eli', 'Dana']]
Explanation: There are 2 (2!) possible arrangements of 2 baristas.

Example 3:

Input: baristas = ['Frank']
Output: [['Frank']]
Explanation: There is only 1 possible arrangement when there's just one barista.

Constraints

  • The input array will contain between 1 and 8 barista names.
  • All barista names will be unique (no duplicates).
  • The function should return all possible permutations of the input array.
  • The order of the permutations in the output doesn't matter, but each permutation should maintain the relative ordering of its elements.

Problem Breakdown

To solve this problem, we need to:

  1. This problem is a classic application of the Ordering Pattern in recursion.
  2. The number of permutations for n distinct elements is n! (n factorial).
  3. We can solve this by recursively placing each available barista in the first position and then finding all permutations of the remaining baristas.
  4. Backtracking is essential to explore all possible arrangements efficiently.
ProblemSolutionCode
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