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Problem Statement

Soup Servings

There are two types of soup: type A and type B. Initially, we have n ml of each type of soup. There are four kinds of operations:

  1. Serve 100 ml of soup A and 0 ml of soup B.
  2. Serve 75 ml of soup A and 25 ml of soup B.
  3. Serve 50 ml of soup A and 50 ml of soup B.
  4. Serve 25 ml of soup A and 75 ml of soup B.

When we serve some soup, we give it to someone, and we no longer have it. Each turn, we will choose from the four operations with an equal probability 0.25. If the remaining volume of soup is not enough to complete the operation, we will serve as much as possible. We stop once we no longer have some quantity of both types of soup.

Note that we do not have an operation where all 100 ml's of soup B are used first.

Return the probability that soup A will be empty first, plus half the probability that A and B become empty at the same time. Answers within 10-5 of the actual answer will be accepted.

Examples

Example 1:

Input: n = 50
Output: 0.62500
Explanation: If we choose the first operation, A will become empty first. If we choose the second operation, A and B will become empty at the same time. If we choose the third operation, B will become empty first. If we choose the fourth operation, B will become empty first. So the probability that A will be empty first plus half the probability that A and B become empty at the same time = 0.25 + 0.25 * 0.5 = 0.375.

Example 2:

Input: n = 100
Output: 0.71875
Explanation: The probability is calculated using dynamic programming, considering all possible operations and their outcomes.

Constraints

  • 0 <= n <= 10^9

Problem Breakdown

To solve this problem, we need to:

  1. This problem can be solved using dynamic programming with memoization.
  2. The key insight is to define a recursive function that calculates the probability for given amounts of soup A and soup B.
  3. We can use memoization to avoid redundant calculations.
  4. For large values of n, the probability approaches 1, so we can return 1 directly for n > 4800.
  5. We can scale down the problem by dividing n by 25 and working with smaller units to simplify the calculations.
ProblemSolutionCode
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